Question

Create a program BloomGrid.java that creates a 5-by-5 2D array, then asks the user for an x and y coordinate. Then, print out the contents of the 2D array, which should have a 3-by-3 plus shape displayed on the grid with the center of the plus being your coordinate. You do not have to make any changes to the grid orientation. If the user places a point at the edge of the grid, you should be able to place any portion of the plus that's still on the grid and not crash.

Answer 1

import java.util.Scanner;

public class BloomGrid {

    static boolean isValid(char[][] grid, int x, int y) {
        return x < grid.length && y < grid[x].length;
    }

    static void set(char[][] grid, int x, int y) {
        if(isValid(grid, x-1, y)) grid[x-1][y] = 'X';
        if(isValid(grid, x, y-1)) grid[x][y-1] = 'X';
        if(isValid(grid, x, y)) grid[x][y] = 'X';
        if(isValid(grid, x, y+1)) grid[x][y+1] = 'X';
        if(isValid(grid, x+1, y)) grid[x+1][y] = 'X';
    }

    static void print(char[][] grid) {
        for(int i = 0; i < grid.length; ++i) {
            for (int j = 0; j < grid[i].length; ++j) {
                System.out.print(grid[i][j] + " ");
            }
            System.out.println();
        }
    }

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        char[][] grid = new char[5][5];
        for(int i = 0; i < grid.length; ++i) {
            for(int j = 0; j < grid[i].length; ++j) {
                grid[i][j] = '.';
            }
        }

        System.out.print("Enter a x-coordinate: ");
        int x = in.nextInt();
        System.out.print("Enter a y-coordinate: ");
        int y = in.nextInt();

        set(grid, x, y);

        print(grid);
    }

}