Calculate the change in internal energy (ΔrU) for the following reaction at 1.00 bar and 298...
Calculate the change in internal energy (ΔrU) for the following reaction at 1.00 bar and 298 K. Express your answer in kJ/mol. ?8?18(?)+17?2(?) → 8??2(?)+9?2?(?) ∆??=−5430??/??l
Homework Answers
Given 
rH = -
5430 kJ/mol
According to 1st law of thermodynamics:
rH =
rU +
P*V
Also P*V =
- n(g)*RT
For the given reaction,
n(g) = (moles of
gaseous products) - (moles of gaseous reactants)
=> n(g) = 8 - 17 = -
9 mol
Now P*V = - (- 9 mol *
8.314 J/mol.K * 298K) = 22298 J/mol * (1kJ / 1000 J) = 22.298
kJ/mol
=> rH =
rU +
P*V
=> rU =
rH -
P*V
=> rU =
−5430 kJ/mol - 22.298 kJ/mol
=> rU = -
5452.3 kJ/mol (Answer)
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