A bowling competition had teams competing for the highest number of strikes during a single bowling game. In reviewing the results of a random sample of teams for this bowling competition, the score keeper found the mean number of strikes was x¯=19, with a margin of error of 3.
Construct a confidence interval for the mean number of strikes.
Provide your answer below:
Solution :
Given that
Point estimate = sample mean =
= 19
margin of error = E = 3
A confidence interval for the mean number of strikes,
±
E
= 19 ± 3
= ( 16, 22 )
A bowling competition had teams competing for the highest number of strikes during a single bowling...
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20.
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