Question

How many milliliters of 0.130  M  H2SO4 are needed to neutralize 0.240 g of NaOH?

Answer 1

The balanced equation is

2 NaOH + H₂SO₄ ---------> Na₂SO₄ + 2 H₂O

Number of moles of NaOH = mass/mol.wt. = 0.240 g/(40.00 g/mol) = 0.006 mol

According to balanced equation,

2 moles of NaOH neutralizes 1 mole of H₂SO₄

So, 0.006 mol of NaOH would neutralize 0.006 mol * ½ = 0.003 mol of H₂SO₄

Number of moles of H₂SO₄ = 0.003 mol

Molarity of H₂SO₄ = 0.130 M = 0.130 mol/L

Volume of H₂SO₄ = 0.003 mol/(0.130 mol/L) = 0.023077 L = 23.07692 mL = 23.1 mL