Question

1. Write code for a function that receives two parameters (a,and b) by value and two more parameters (c and d) by reference. All parameters are double.
The function works by assigning c to (a/b) and assigning d to (a*b). The function has no return value.

From main, use scanf to get two numbers, then call the function, and then display both outcome values to the output in a printf statement.

2. After part 1 is completed, write code to get 20 integer numbers from the user. The code then displays how many of those numbers are above the average. To get proper credit you must follow these steps:

a. write a for loop to fill the array with numbers from the user. Use an array for this.

b. use a pointer to calculate the average of the numbers entered into the array of part a above, in another loop.

c. write a function, then pass the array, its size, and the average to that function. The function arguments would be a pointer to int, an int, and a float and it returns the count of the number of elements that are above the average.

Answer 1

Question 1:

Answer:

#include <iostream>

using namespace std;

//function to calculate division and multiplication using reference variable
void calculateValues(double a, double b, double &c, double &d)
{
c = a / b;
d = a * b;
}
int main()
{
//variable declaration
double a, b, c, d;
  
//display message
printf("Enter the first number: ");
scanf("%lf", &a);
  
//display message
printf("Enter the second number: ");
scanf("%lf", &b);
  
//function calling
calculateValues(a, b, c, d);
  
//display result
printf("\na / b = %.2lf", c);
printf("\na * b = %.2lf", d);

return 0;
}

OUTPUT:

Question 2:

Answer:

#include <iostream>

using namespace std;

//function to count the number above average
int countAboveAvg(int a[], int size, float avg)
{
int count=0;
for(int i=0; i<20; i++)
{
if(a[i] > avg)
{
count++;
}
}
  
//return statement
return count;
}

int main()
{
//array and variable declaration
int num[20], total = 0, aboveAvg;
float avg;
  
//display message
cout<<"Enter 20 integer numbers: "<<endl;
for(int i=0; i<20; i++)
{
cin>>num[i];
}
  
for(int i=0; i<20; i++)
{
total = total + *(num+i);
}
  
avg = total / 20;
  
//function calling
aboveAvg = countAboveAvg(num, 20, avg);
  
//display result
printf("\nThe number of elements above average is: %d", aboveAvg);

return 0;
}

OUTPUT: