Question

Fix the following program so that input is from a file “c:\comp\asg1\stalls.txt” and output is from a file “c:\comp\asg1\stalls_output.txt”

#include <iostream>

#include <fstream>

using namespace std;

struct Stall {
string name;
double income;
double expenses;
double net;
};

int main()
{

double tprofit_loss = 0, most_profit;
Stall tmp;
int n = 0;
Stall Stalls[100];
bool loop = true;

ifstream f;
f.open("stalls.txt");

ofstream of;
of.open("output.txt");

while (loop) {
f >> tmp.name;

if (tmp.name == "XXXXXX" || tmp.name == "xxxxxx") {
loop = false;
continue;
}

f >> tmp.income; // read income from the file
f >> tmp.expenses; // read expenses from the file

tmp.net = tmp.income - tmp.expenses;
tprofit_loss += tmp.net;

Stalls[n] = tmp;

n++;
}

for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
if (Stalls[i].net < Stalls[j].net) {
Stall tmp = Stalls[i];
Stalls[i] = Stalls[j];
Stalls[j] = tmp;
}
}
}

of << "Stall name\t"
<< "Net income" << endl;

for (int i = 0; i < n; i++)
of << Stalls[i].name << "\t\t" << Stalls[i].net << endl;

of << "Number of stalls in the bazar were: " << n << endl;
if (tprofit_loss < 0)
of << "Total loss of bazar is " << tprofit_loss << endl;
else
of << "Total profit of bazar is " << tprofit_loss << endl;

of << "Stall with most profit is:" << endl;
most_profit = Stalls[n - 1].net;

for (int i = n - 1; i >= 0 && Stalls[i].net == most_profit; i--)
of << Stalls[i].name << endl;
  
of << "Stalls with profits: "<<endl;
for (int i = 0; i < n; i++)
{
if ((Stalls[i].net) > 0)
of << Stalls[i].name << endl;
}
of << endl;

of << "Order:"<<endl;
  
for (int k = 0; k < n; k++)
for (int i = 0; i < n; i++){
if (Stalls[i].net < 0)
{
for (int j = i + 1; j < n; ++j){
Stalls[j - 1] = Stalls[j];
               }
               n--;
}
}
for (int i = 0; i < n; i++) {
       for (int j = i + 1; j < n; j++) {
if (Stalls[i].net > Stalls[j].net) {
Stall tmp = Stalls[i];
Stalls[i] = Stalls[j];
Stalls[j] = tmp;
}
}
}
for (int i = 0; i < n; i++)
of << Stalls[i].name << endl;

of << endl;
return 0;
}

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

#include <iostream>

#include <fstream>

using namespace std;

struct Stall {

    string name;

    double income;

    double expenses;

    double net;

};

int main()

{

    double tprofit_loss = 0, most_profit;

    Stall tmp;

    int n = 0;

    Stall Stalls[100];

    bool loop = true;

    ifstream f;

    //reading input from c:\comp\asg1\stalls.txt

    //note that, all \ characters have been replaced with \\

    //because \ alone is an escape character (used in \n, \t etc),

                // whereas \\ represents \ character

    f.open("c:\\comp\\asg1\\stalls.txt");

               

                //storing output in c:\comp\asg1\stalls_output.txt, same rules applicable

    ofstream of;

    of.open("c:\\comp\\asg1\\stalls_output.txt");

               

                //before entering loop, I suggest that you check if the file is opened correctly

                //this can be done by calling if(!f){ file not opened. do something or quit }else { file

                //opened }

    while (loop) {

        f >> tmp.name;

        if (tmp.name == "XXXXXX" || tmp.name == "xxxxxx") {

            loop = false;

            continue;

        }

        f >> tmp.income; // read income from the file

        f >> tmp.expenses; // read expenses from the file

        tmp.net = tmp.income - tmp.expenses;

        tprofit_loss += tmp.net;

        Stalls[n] = tmp;

        n++;

    }

    for (int i = 0; i < n; i++) {

        for (int j = i + 1; j < n; j++) {

            if (Stalls[i].net < Stalls[j].net) {

                Stall tmp = Stalls[i];

                Stalls[i] = Stalls[j];

                Stalls[j] = tmp;

            }

        }

    }

    of << "Stall name\t"

       << "Net income" << endl;

    for (int i = 0; i < n; i++)

        of << Stalls[i].name << "\t\t" << Stalls[i].net << endl;

    of << "Number of stalls in the bazar were: " << n << endl;

    if (tprofit_loss < 0)

        of << "Total loss of bazar is " << tprofit_loss << endl;

    else

        of << "Total profit of bazar is " << tprofit_loss << endl;

    of << "Stall with most profit is:" << endl;

    most_profit = Stalls[n - 1].net;

    for (int i = n - 1; i >= 0 && Stalls[i].net == most_profit; i--)

        of << Stalls[i].name << endl;

    of << "Stalls with profits: " << endl;

    for (int i = 0; i < n; i++) {

        if ((Stalls[i].net) > 0)

            of << Stalls[i].name << endl;

    }

    of << endl;

    of << "Order:" << endl;

    for (int k = 0; k < n; k++)

        for (int i = 0; i < n; i++) {

            if (Stalls[i].net < 0) {

                for (int j = i + 1; j < n; ++j) {

                    Stalls[j - 1] = Stalls[j];

                }

                n--;

            }

        }

    for (int i = 0; i < n; i++) {

        for (int j = i + 1; j < n; j++) {

            if (Stalls[i].net > Stalls[j].net) {

                Stall tmp = Stalls[i];

                Stalls[i] = Stalls[j];

                Stalls[j] = tmp;

            }

        }

    }

    for (int i = 0; i < n; i++)

        of << Stalls[i].name << endl;

    of << endl;

    return 0;

}