For the cell schematic below, identify values for n and Q, and calculate the cell potential,...
For the cell schematic below, identify values for n and Q, and calculate the cell potential, Ecell.
Al(s)│Al3+(aq,0.15M)║Cu2+(aq,0.025M)│Cu(s)
Homework Answers
At anode :
Oxidation : Al (s) --------------> Al3+ (aq) + 3e-
At cathode :
Reduction : Cu2+ (aq) + 2e- -------------> Cu (s)
Overall reaction :
2 Al (s) + 3 Cu2+ (aq) ------------> 2 Al3+ (aq) + 3 Cu (s)
Eocell = Eored - Eooxidation
= 0.34 - (- 1.66)
Eocell = 2.00 V
Q = [Al3+]^2 / [Cu2+]^3
= (0.15)^2 / (0.025)^3
Q = 1440
Q = 1.44 x 10^3
number of electrons , n = 6
Ecell = Eo - 0.05196 / 6 log Q
= 2.00 - 0.05196 / 6 log (1440)
Ecell = 1.97 V
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For the cell schematic below, identify values for n and Q, and
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