Using the equation: ΔG° = -nFE°cell calculate ΔG° and indicate if the reaction below is spontaneous...
Using the equation:
ΔG° = -nFE°cell
calculate ΔG° and indicate if the reaction below is spontaneous or non spontaneous:
Al(s) | Al3+ (0.0020 M) | | Cu2+ (0.10 M) | Cu(s)
The reduction potentials for the half reactions are
Al3+(aq) + 3e- --> Al(s) = -1.662 V
Cu2+(aq) +2e- --> Cu(s) = +0.3419 V
Homework Answers
E° = 0.3419+(-1.662)
= 2.0039 V
∆G° = - nFE°
= -6×96485×2.0039
= -1160.1 kJ
Reaction is.spontaneous
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Using the equation:
ΔG° = -nFE°cell
calculate ΔG° and indicate if the reaction below is spontaneous...
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A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
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I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help...
I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
thank you so much
An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
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need help for half cell potentials pls calculate step by step (NOTE - Remember that the...
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I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
thank you so much
An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
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need help for half cell potentials pls calculate step by step
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