Please help!
Question 1 Hess's Law Calculate the delta H'298 for the calcining of limestone CaC03 (s, calcite) -> Cao (s) + CO2 (g) using the following data:
CaC03 (s, calcite)delta H'298 = -1206.92 kJ/mol
CaO (s) delta H'298 = -635.09 kJ/mol
CO2 (g)delta H'298 = -393.509 kJ/mol
Please help! Question 1 Hess's Law Calculate the delta H'298 for the calcining of limestone CaC03...
Use Hess's law to calculate standard enthalpy change of formation at 298K for carbon (iv) sulphide compound, Cs2. Given that: Cs2(s) + 3O2(g) - Co2(g) + 2So2(g) ∆H°298= -1113KJ/mol C(s) + O2(g) - Co2(g). ∆H°298 = -407 KJ/mol S(s) + O2(g) - So2(g) ∆H°298 = -298 KJ/mol
Calculate DELTA H of reacton for Ca (s) + 02 (g) + CO2 (g)--> CaCO3 (s) given the following set of reactions: Ca (s) 02 (g) -> CaO(s) Delta H -635.1 kJ / mol CaC03(s) > Cao (s) + CO2 (g) Delta H 178.3kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Use Hess's Law to determine Delta H for the reaction 2 Al(s) + 3 Cl_2(g) rightarrow 2 AlCl_3(s) given: 2 Al(s) + 6 HCl(aq) rightarrow 2 AlCl_3(aq) + 3 H_2(g) Delta H = -1049 kJ HCl(g) rightarrow HCl(aq) Delta H = -74.8 kJ H_2(g) + Cl_2(g) rightarrow 2 HCl(g) Delta H = -185 kJ AlCl_3(s) rightarrow AlCl_3(aq) Delta H = -323 kJ
The next three questions will take you through the calculation of Delta H for the following reaction using Hess's Law. Follow the steps and answer each question in turn. 2BaCO3 (s) -----> 2Ba (s) + O2(g) + 2CO2 (g) AH = ? Given the following reactions and thermochemical data: 1. Bao (s) + CO2 (g) -------> BaCO3(s) AH = - 277.4 kJ 2. 2 Bao (s) -------> 2 Ba (s) + O2(g) AH = + 1096.2 kJ After rearranging as/if...
1. Using the reactions given below please calculate the change in enthalpy (delta H) for the stated reaction. Stated Reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) delta H = ?! Given Reactions & Enthalpy Changes: 2 Fe(s) + 3/2 02(g) → Fe2O3(s) 2 Fels) * delta H = -824.2 kJ delta H = -282.7 kJ CO(g) + 4 02(g) → CO2(g) 2. Using the reactions given below please calculate the change in enthalpy (delta H) for...
The next three questions will take you through the calculation of Delta H for the following reaction using Hess's Law. Follow the steps and answer each question in turn 2Baco, (s) -----> 2Ba (s) + O2(g) + 2CO2 (g) AH = ? Given the following reactions and thermochemical data: 1. BaO (8) + CO2 (g) ----ảy> BaCO3 (5) AH = 274 VI 2. 2 Bao (s) -------> 2 Ba (s) + O2(g) AH + 1096.2 kJ After rearranging as if...
The reaction between lime (CaO(s)) and carbon dioxide (CO2(g)) forms the predominant mineral in limestone, CaCO3(s), (Delta Hrxn° = −177.1 kJ/mol, Delta Srxn° = −158.2 J/K∙mol). Lime is a key component in making concrete and is made from limestone. What is the minimum temperature required to shift the equilibrium toward lime (CaO(s)) from limestone (CaCO3(s))?
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol