Given the following:
phosphocreatine → creatine + Pi ΔG = −43.0 kJ/mol
ATP → ADP + Pi ΔG = −30.5 kJ/mol
What is the overall ΔG for the following Reaction?
phosphocreatine + ADP → creatine + ATP
A) -12.5 kJ/mol
B) + 73.5 kJ/mol
C) -73.5 kJ/mol
D) + 12.5 kJ/mol
Given the following: phosphocreatine → creatine + Pi ΔG = −43.0 kJ/mol ATP → ADP + Pi...
2. For the following reaction: ATP+ creatine + H2O creatine phosphate + ADP + P, The relevant half reactions are: ATP → ADP + Pi Creatine phosphate + H2O-> creatine AG-30.5 kJ/mol ΔG°,--43.1 kJ/mol a. (2 pts.) Calculate the ΔG°, for the overall reaction. b. (2 pts.) Is the reaction spontaneous or non-spontaneous? Endergonic or exergonic?
7. Consider the reactions below and their given standard free-energy changes. Phosphocreatine ↔ creatine + P i Δ G' ° = –43.0 kJ/mol ATP ↔ ADP + P i Δ G' ° = –30.5 kJ/mol A) What is the overall Δ G' ° for the following reaction? Phosphocreatine + ADP ↔ creatine + ATP B) Explain how phosphocreatine can be used as a kind of mechanism to STORE excess ATP during periods of rest. Why might this be necessary?
2. Hydrolysis of 0.5 M studentose catalyzed by teacherase to become successose is 95% complete at equilibrium (i.e., only 5% of the studentose remains). What is AG"? (R = 8.315 J/mol K; T = 298 K) 3. The standard free-energy changes for the reactions below are given. Phosphocreatine creatine + Pi AG"=-43.0 kJ/mol ATP → ADP + Pi AG" = -30.5 kJ/mol The overall AG" for the reaction: Phosphocreatine + ADP creatine + ATP, is _ A) -73.5 kJ/mol C)...
Consider the following reactions: #1: ATP + H2O -> ADP +P, #2: Phosphocreatine + H20 — #3: Phosphocreatine + ADP — creatine + P creatine + ATP (AG" =-31 kJ/mol) (4Gº = -43 kJ/mol) (AG'= -12 klimol) AG" for reaction #3 would be 12 km 0-12 kJimo 0 -43 kJimo 0 74 klimo
ATP + H2O <---> ADP + Pi Calculate the ΔG for ATP hydrolysis when the concentrations of ATP, ADP, and Pi are all 1M R = 1.98 x 10-3 T = 310 kelvin ΔGº = -30.5 kJ/mol
The standard free energy (ΔG∘′)(ΔG∘′) of the creatine kinase reaction is −12.6 kJ⋅mol−1.−12.6 kJ⋅mol−1. The ΔGΔG value of an in vitro creatine kinase reaction is −0.1 kJ⋅mol−1.−0.1 kJ⋅mol−1. At the start of the reaction, the concentration of ATP is 6 mM,6 mM, the concentration of creatine is 12 mM,12 mM, and the concentration of creatine phosphate is 25 mM.25 mM. Using the values given, calculate the starting concentration of ADP in micromolar.
For the reaction ATP + H2O ⇔ ADP + phosphate, ΔG° = -30.5 kJ/mol. Very high concentrations of ADP and phosphate (such that Q>>K) would likely have which of the following effects (explain your thinking): a. ΔG would be less negative than ΔG°, because conditions would disfavor the formation of more ADP b. ΔG would be more negative than ΔG°, because conditions would favor the formation of more ADP c. ΔG° and ΔG are unrelated in this case, because conditions...
For the hydrolysis of ATP to ADP + Pi (AGº'=-30.5kJ/mol) what is AG'when [ATP], [ADP], and [Pi] are 8, 1, and 8 mM, respectively (use RT=2.48 kJ/mol). O Select one: A. -30.5 kJ/mol x O B.-17.1 kJ/mol C. -47.6 kJ/mol D. 13.4 kJ/mol O
10) The AG for the hydrolysis of creatine phosphate is -43.1 k/mol, whereas the AG for ATP synthesis is+30.5 kj/mol, what is the overall ΔG., for the reaction shown below? creatine + ATP creatine phosphate+ADP O-73.6 kj/mol O12.6 k/mol -43.1 k/mol O73.6 k/mol -12.6 kj/mol 043.1 Wmol Answer not listed
If the ΔG°' for ATP hydrolysis is –30 kJ/mol and the ΔG°' for phosphoenolpyruvate hydrolysis is –62 kJ/mol, what is the ΔG°' for the phosphorylation of ADP by phosphoenolpyruvate? a) -32 kJ/mol b) -62 kJ/mol c) +31 kJ/mol d) +92 kJ/mol e) -92 kJ/mol Please provide the appropriate calculation and show the reactions that are involved + the overall reaction. Thank you!