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The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57,...

The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57, and 60. The new process had yields of 54, 56, 52, 56, 53, 51, 54, 53, and 52. Does the new process have a better S/N ratio?

a

Y

b

N

0 0
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Answer #1

The yield (larger-the-better) on an old chemical process for five days is 61, 63, 58, 57, and 60.

S/N ratio =

= 59.8/2.1354

= 28

The new process had yields of 54, 56, 52, 56, 53, 51, 54, 53, and 52.

S/N ratio =

= 53.4444/1.6405

= 32.58

Yes, the new process have a better S/N ratio.

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