A bullet is fired horizontally with an initial velocity of 865 m/s at a target located...

Question

Question

A bullet is fired horizontally with an initial velocity of 865 m/s at a target located 150 m from the rifle.

A) How much time is required for the bullet to reach the target?

B) How far does the bullet fall in this time?

science physics

Answer 1

Answer #1

horizontal velocity = V0x = VX = 865 m/sec

horizontal distance = range = x=150 m

a) Range = V0X * t

time = x / vox = 150 / 865 = 0.173 sec

b) distance = y = V0y * t + 1/2 * g * t^2

y = 0 + 1/2 * 9.8 * 0.173^2

y = 0.29 m

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Answer 2

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