A rifle is fired straight up, and the bullet leaves the rifle with an initial velocity...
A rifle is fired straight up, and the bullet leaves the rifle with an initial velocity magnitude of 724 m/s. After 5.00 s the velocity is 675 m/s. At what rate is the bullet decelerated?
Homework Answers
We have Newton’s motion formula, v = u + at
where v is final velocity,
u is initial velocity,
a is acceleration and
t is time
thus for above question, 675 = 724 + a*5
==> 5a = 675-724
==>5a = -49
Therefore, a = -49/5 = -9.8 m/s2[Answer]
Negative sign indicates retardation. If magnitude is asked in answer just put 9.8 m/s2 and if both magnitude and direction is asked put -9.8 m/s2.
Note: the value we got is value of acceleration due to gravity and which is true.
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