x -1 3 5 8 9
p(x) 0.2 0.1 0.4 0.2 0.1
1 list the values that x may assume (use ascending order)?
2 what value of x is most probable?
3 what is the probability that x is greater than 0?
4. what is the probability that x=1?
solution
1) ascending order x value = -1 3 5 8 9
2) x=3,5
3)P(x > 0)= p(x=3)+p(x=5)+p(x=8)+p(x=9)
=0.1+0.4+0.2+0.1
=0.8
probability=0.8
4)p(x=1) =0.0
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