Question

convert this python code to c++ code def sort(a,b): if a > b: return b,a else:...

convert this python code to c++ code

def sort(a,b):
if a > b:
return b,a
else:
return a,b

def main():
set1 = input('Enter the first pair of integers: ')
set2 = input('Enter the second pair of integers: ')
set3 = input('Enter the third pair of integers: ')

set1 = set1.split(',')
set1_0 = int(set1[0])
set1_1 = int(set1[1])

set2 = set2.split(',')
set2_0 = int(set2[0])
set2_1 = int(set2[1])

set3 = set3.split(',')
set3_0 = int(set3[0])
set3_1 = int(set3[1])
  
print(sort(set1_0,set1_1))
print(sort(set2_0,set2_1))
print(sort(set3_0,set3_1))

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Answer #1

Thanks for the question.


Below is the code you will be needing Let me know if you have any doubts or if you need anything to change.


Thank You !


===========================================================================

#include<iostream>
using namespace std;

// function accepts the numbers as reference
void sort(int&a, int&b){
  
   if(a>b){
       int temp = a;
       a=b;
       b=temp;
   }
}

int main(){
  
   int a,b;
   int x,y;
   int m,n;
  
   cout<<"Enter the first pair of integers: ";
   cin>>a>>b;
  
   cout<<"Enter the second pair of integers: ";
   cin>>x>>y;
  
   cout<<"Enter the third pair of integers: ";
   cin>>m>>n;
  
   sort(a,b);
   sort(x,y);
   sort(m,n);
  
   cout<<endl;
   cout<<a<<" "<<b<<endl;
   cout<<x<<" "<<y<<endl;
   cout<<m<<" "<<n<<endl;
  
  
  
}

let me know if you have any doubts or if you need anything to change.

If you are satisfied with the solution, please rate the answer.

Thanks!


===========================================================================

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