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A motor attached to a 120 V/60 Hz power line draws an 7.50 A current. Its...

A motor attached to a 120 V/60 Hz power line draws an 7.50 A current. Its average energy dissipation is 840 W. Part APart complete What is the power factor? 0.933 Part B complete What is the rms resistor voltage? 112 V Part C What is the motor's resistance? nothing ΩΩ Request Answer Part D How much series capacitance needs to be added to increase the power factor to 1.0? nothing μF

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Answer #1

A)

Power factor = 840/(120 x 7.5) = 0.933

B)

RMS voltage, Vrms = 840/7.5 = 112 V

C)

Resistance, R = 112/7.5 = 14.93 ohm

D)

Power factor = sqrt((120 x 7.5)^2 - 840^2) = 323.11 VAR

Xl = 323.11/7.5^2 = 5.74 ohm

C = 1/(2 pi x 60 x 5.74) = 461.79 μF

Comment in case any doubt please rate my answer....

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