4. In Drosophila melanogaster, the phenotype curly wings is due
to a mutant allele Cy that is lethal when homozygous. A population
is established with an initial frequency of Cy equal to 0.168.
Denoting + as the wild- type (i.e. non-mutant) allele at this
locus, calculate the expected frequency of Cy in the next
generation if the relative fitness of the ++ homozygote to the Cy/+
heterozygote is:
a) 1 : 1
b) 1 : 0.5
c) Briefly explain why the change in frequency of the Cy allele is
greater in one case than the other.



C. Frequency of Cy allele is found to be greater in the part b where the relative fitness of heterozygotes i.e. Wcy/+ is given as 0.5. This is a clear example of heterozygote advantage which is described as the selection of individuals with heterozygote genotype over other genotypes as heterozygosity increases the chances of survival of a living being. So, those individuals who have heterozygote genotype, are more genetically fit than others.
4. In Drosophila melanogaster, the phenotype curly wings is due to a mutant allele Cy that...
In Drosophila melanogaster, the phenotype “curly wings” is due to a dominant allele Cy that is lethal when homozygous. A population is established with an initial frequency of Cy equal to 0.168. Calculate the expected frequency in the next generation, assuming: that the relative fitness (w) of +/+ and Cy/+ are both 1.0 that the relative fitness (w) of +/+ is 1.0 and Cy/+ is 0.5
The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by an autosomal recessive mutant allele that independently assorts with an autosomal recessive mutant allele for hairy (h) body. A parental cross was made between a fly that is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed to each other and produced 1536 offspring. The phenotypes of the F2...
The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by an autosomal recessive mutant allele that independently assorts with an autosomal recessive mutant allele for hairy (h) body. A parental cross was made between a fly that is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed to each other and produced 1536 offspring. The phenotypes of the F2...
In Drosophila, glued eyes is due to a dominant allele Ge that is lethal when homozygous. A population is established with an initial frequency of Ge equal to 0.178. Calculate the expected frequency in the next generation (p’) assuming: a. The relative fitness of +/+: Ge/+ is 1:1 b. the relative fitness of +/+: Ge/+ is 1:0.5
The Curly (Cy) mutant in fruit flies causes curled up wings. This mutant is due to an autosomal dominant mutation that exhibits 80% penetrance. The miniature body (m) phenotype is due to an X-linked recessive mutation and is completely penetrant. A male with normal body size and heterozygous for the Cy mutation is crossed to a female with normal wings and miniature body. What is the probability of obtaining progeny flies from this cross that are males with miniature bodies...
1. In Drosophila (fruit flies) Curly (c) wings are recessive and normal (C) wings are dominant. If you cross curly wing flies with homozygous normal wing what is the expected genotype and phenotype of the F1 generation? What is the expected phenotypic ratio of the F2 generation?
Purple eyes (or), black body (b) and vestigial wings (vg) are recessive alleles in Drosophila melanogaster. Apr prb bvg" vg trihybrid is crossed to a fly homozygous for the recessive allele at each locus. The following numbers of offspring are observed. Phenotype Number of progeny Unordered genotypes Ordered genotypes Wild type 92 188 1241 vg 7 pr, b 8 pr, vg 1243 b, vg 190 pr, b, vg Total: 2990 1. Write the full, unordered genotypes of each category Comit...
Purple eyes (pr), black body (b) and vestigial wings (vg) are recessive alleles in Drosophila melanogaster. Apr pr b' bvg' vg trihybrid is crossed to a fly homozygous for the recessive allele at each locus. The following numbers of offspring are observed. Phenotype Number of progeny Unordered genotypes Ordered genotypes Wild type 188 1241 vg pr, b pr, vg 1243 b, vg 190 88 pr, b, vg Total: 2990 1. Write the full, unordered genotypes of each category (omit the...
Genetic Linkage The six genes listed below are all located on Chromosome 2 of Drosophila melanogaster. Your goal is to construct a genetic map of Chromosome 2. That is, determine the order of these genes along chromosome 2 and the map distance in centimorgans between each gene. To complete this task, you will be given the results of a variety of two-point test crosses involving these genes. For each test cross you may assume that the female is heterozygous and...
In Drosophila (fruit flies) the genes how, dumpy and ebony are located on chromosome 3. LOF = loss of function. Flies homozygous for a LOF mutation (no gene product made) in ebony have dark black bodies. Flies homozygous for a LOF mutation (no gene product made) in dumpy have truncated (short) wings. Flies homozygous for a partial LOF mutation (some gene product made but significantly less than normal) in how have wings that will not fold down (held out wings;...