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Albinism, the total lack of pigment, is due to a recessive gene. A man and woman...

Albinism, the total lack of pigment, is due to a recessive gene. A man and woman plan to marry and wish to know the probability of their having any albino children. What are the probabilities if: a. both are normally pigmented, but each has one albino parent. b. the man is an albino, the women is normal, but her father is an albino. (Draw pedigrees to explain)

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Answer #1

Let, Normal allele = A, albino allele = a

As albinism occurs as autosomal recessive disorder, AA & Aa will have normal pigment & aa will develop albinism.

a) Both are normally pigmented, but each has one albino parent:

As they both have one albino parent (Assuming their father is affected) they will be heterozygous for albino allele, i.e., Aa. This is shown in the below pedigree.

The cross between two heterozygotes is shown in the below Punnett square.

Gametes A a
A AA (Normal pigment) Aa (Normal pigment)
a Aa (Normal pigment) aa (Albinism)

So, probability that their child will develop albinism is 1/4 or 0.25.

b) The man is an albino, the women is normal, but her father is an albino:

Man's genotype will be aa. Women will be heterozygous (Aa) as her father is albino. This is shown in the below pedigree.

The cross between aa & Aa is shown in the below Punnett square.

Gametes a a
A Aa (Normal pigment) Aa (Normal pigment)
a aa (Albinism) aa (Albinism)

So, probability that their child will develop albinism is 2/4 or 0.5.

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