Question

Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by this equation:

4 NH3 (g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (g)

If 2.0 g of NH3 react in excess oxygen, how many grams of NO will be produced?

Answer 1

mass NH₃ = 2.0 g

moles NH₃ = (mass NH₃) / (molar mass NH₃)

moles NH₃ = (2.0 g) / (17.0 g/mol)

moles NH₃ = 0.118 mol

moles NO produced = moles NH₃ consumed

moles NO produced = 0.118 mol

mass NO produced = (moles NO produced) * (molar mass NO)

mass NO produced = (0.118 mol) * (30 g/mol)

mass NO produced = 3.5 g