Nitric oxide, (NO), is made from the oxidation of NH3, and the reaction is represented by the unbalanced equation:
NH3+O2 ---> NO+H2O
Balance the equation and determine what mass of H2O, in g, can be produced from 1.33 g of NH3
Balance eqaution is
4NH3 + 3O2 --------->4 NO + 2h2o
Mass of nh3= 1.33g
Mole of nh3= mass/molarmass
Mole = 1.33g/17g/mol = 0.0782 mol nh3
In balance equation the ratio between nh3 and h2o is 4:2
Then 0.0782 mole nh3 *(2 mol h2o/4mol nh3) *18g/mol h2o
= 0.704 g h2o is produced
Nitric oxide, (NO), is made from the oxidation of NH3, and the reaction is represented by...
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How will you obtain your nitric oxide for this experiment? The nitric oxide will be generated by the reaction of copper with dilute nitric acid according to this equation. 3 Cu(s) +8H(aq) + 2NO3 (aq) ---> 2NO(g) + 3 Cu²+ (aq) + 4H2O(1) The nitric oxide gas will be taken from a storage bottle provided by the TA. The nitric oxide gas will be collected from a gas cylinder. The nitric oxide gas will be prepared by the reaction of...
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3 ) over a catalyst with excess oxygen (02) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: ?NH, (g)+?O2(g) +?NO(g)+?H2O(g) Part A What volume of O2 at 684 mmHg and 39 °C is required to synthesize 19.0 mol of NO? Express your answer to three significant figures and include the appropriate units. View Available Hint(s)...
The industrial production of nitric acid (HNO3) is a multistep process. The first step is the oxidation of ammonia (NH3) over a catalyst with excess oxygen (O2) to produce nitrogen monoxide (NO) gas as shown by the unbalanced equation given here: NH3(g)+?O2(g)→?NO(g)+?H2O(g) What volume of O2 at 722 mmHg and 27 ∘C is required to synthesize 17.5 mol of NO?