Debug to print output "2 3 5 6 8 11": #include <stdio.h> #include <stdlib.h> int main()...
Debug to print output "2 3 5 6 8 11":
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i, j, n;
int A[] = {2, 3, 5, 5, 5, 6, 8, 11, 11, 11};
n = sizeof(A) / sizeof(int);
for (i = 0; i < n - 1; i++){
if (A[i] != A[i + 1]) {
for (j = 1; j
< n - 1; j++) {
A[j] = A[i];
}
j++;
n--;
i--;
}
}
for (i =0; i < n; i++) {
printf("%d\n", A[i]);
}
return 0;
}
Homework Answers
ANSWER: Here I corrected the code and remove the duplicate items from the array and print it Please like it.
CODE:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i, j,k, n;
int A[] = {2, 3, 5, 5, 5, 6, 8, 11, 11, 11};
n = sizeof(A) / sizeof(int);
for (i = 0; i < n; i++){
for (j = i+1; j < n; j++) {
if(A[i]==A[j])
{
for(k=j;k<n;k++){
A[k]=A[k+1];
}
n--;
j--;
}
}
}
for (i =0; i < n; i++) {
printf("%d ", A[i]);
}
return 0;
}
OUTPUT:
Add Answer to:
Debug to print output "2 3 5 6 8 11":
#include <stdio.h>
#include <stdlib.h>
int main()...
What is the output? #include <sys/types.h> #include <sys/wait.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> int main()...
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#include <stdio.h>
#include <sys/time.h>
#define DEBUG 1 //Constant is defined for true
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
//if statement is added
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gettimeofday(&start,0);
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{
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OPERATING SYSTWM
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#include <stdio.h>
#include <sys/time.h>
#define DEBUG 1 //Constant is defined for true
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
//if statement is added
if(DEBUG){
gettimeofday(&start,0);
}
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
//if statement added
if(DEBUG){
gettimeofday(&loopstart,0); //measuring time at start of
loop
}
for(int j=0;j<1000000;j++); //outer loop to...
what is output
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