What is the output?
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main()
{
int x = 5;
int y = 2;
int z = 30;
x = fork();
y = fork();
if (x != 0)
printf("Type 1\n");
if (y != 0)
printf("Type 2\n");
z = fork();
if (x > 0 || y > 0 || z > 0)
printf("Type 3\n");
if (x == 0 && y == 0 && z != 0)
printf("Type 4\n");
if (x != 0 && y != 0 && z != 0)
printf("Type 5\n");
return 0;
}
Firstly, we need to understand what fork() do ?
So, basically fork() is used to create another process (also known as child process) which is similar to the first one and it runs unitedly.
No. of process for fork() = 2^n
where n = no. of fork functions.
Output:

Whenever we call fork() for a value assigned variable,it makes same another process with same variable, but it assigns an arbitrary value to the variable of child process.
What is the output? #include <sys/types.h> #include <sys/wait.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> int main()...
Source code to modify:
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
int main()
{
pid_t pid;
/*fork a child process*/
pid = fork();
if (pid<0){ /*error occured*/
fprintf(stderr,"Fork failed\n");
return 1;
}
else if (pid == 0) { /*child process */
printf("I am the child %d\n",pid);
execlp("/bin/ls","ls",NULL);
}
else { /*parent process */
/*parent will wait for the child to complete*/
printf("I am the parent %d\n",pid);
wait(NULL);
printf("Child Complete\n");
}
return 0;
}
1. Write program codes for 3.21 a and...
With explanation Please.
#include #include <sys/types.h> <unistd.h> int main void ) fork fork fork execip ( "/bin/ls", return 0 /* Line A /* Line B/ /*Line C/ /. Line D ./ "ls", NULL); Answer the following: (a) Including the initial parent process, how many processes are created by the program? (b) Answer (a) assuming that lines C and D are interchanged in the program (c) Answer (a) assuming that lines B and D are interchanged (instead of C and D)...
Problem la Points (20) Draw the process tree for the program shown below. #include<sys/types.h> #include<stdio.h> #include<unistd.h> int value = 5; int main() pid_t pid; pid = forko; if(pid ==0) { */ Child Process */ forkO; value += 15; return 0; else if (pid > 0) {/* Parent process */ forkO; forkO; wait(NULL); printf("Parent: value = %d", value); /* LINE A */ return 0;
#include <sys/types.h> #include <sys/ipc.h> #include <sys/shm.h> #include <sys/wait.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include<time.h> void insertionSort(int arr[], int n); void merge(int a[], int l1, int h1, int h2); void mergeSort(int a[], int l, int h) { int i, len=(h-l+1); //Using insertion sort for small sized array if (len<=5) { insertionSort(a+l, len); return; } pid_t lpid,rpid; lpid = fork(); if(lpid<0) { //Lchild proc not created perror("Left Child Proc. not created\n"); _exit(-1); } else if (lpid==0) { mergeSort(a,l,l+len/2-1); _exit(0); } else...
Debug to print output "2 3 5 6 8 11": #include <stdio.h> #include <stdlib.h> int main() { int i, j, n; int A[] = {2, 3, 5, 5, 5, 6, 8, 11, 11, 11}; n = sizeof(A) / sizeof(int); for (i = 0; i < n - 1; i++){ if (A[i] != A[i + 1]) { for (j = 1; j < n - 1; j++) { A[j]...
Suppose that you have three programs that are suppose to print a house diagram in a collaborative manner. (i) prog1.c #include <stdio.h> /* Input/Output */ #include <stdlib.h> /* General Utilities */ int main() { printf(“ ^^^^^^^^^^^^ \n”); printf(“ ^^^^^^^^^^^ ^^^^^^^^^^^ \n”); printf(“^^^^^^^^^^^ ^^^^^^^^^^^ \n”); printf(“ | | \n”); printf(“ | | \n”); exit(1); } (i) prog2.c #include <stdio.h> /* Input/Output */ #include <stdlib.h> /* General Utilities */ int main() { printf(“ | | ...
Combine two codes (code 1) to get names with(code 2) to get info: Code 1: #include<unistd.h> #include<sys/types.h> #include<sys/stat.h> #include<fcntl.h> #include<dirent.h> #include<stdio.h> #include<stdlib.h> void do_ls(char []); int main(int argc,char *argv[]) { if(argc == 1) do_ls("."); else while(--argc){ printf("%s:\n",*++argv); do_ls(*argv); } } void do_ls(char dirname[]) { DIR *dir_ptr; struct dirent *direntp; if((dir_ptr = opendir(dirname)) == NULL) fprintf(stderr,"ls1:cannot open %s\n",dirname); else { while((direntp = readdir(dir_ptr)) != NULL) printf("%s\n",direntp->d_name); closedir(dir_ptr); } } ____________________________ code 2: #include <stdio.h> #include <sys/types.h> #include <sys/stat.h> void show_stat_info(char *,...
Systems Programming Purpose: Understand the fork() regarding its returning values, global/local variables declared in the parent's process, and processing Instruction: Attached is a lab.c file containing a fork() statement. Compile and run it. Explain the output of this program. Thing to submit: Submit a word file to explain the following questions: When fork() is executed, what is happening to the returning values in parent and in child? After fork() is executed, how many more process is created? What is the...
devmem2.c
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <errno.h>
#include <signal.h>
#include <fcntl.h>
#include <ctype.h>
#include <termios.h>
#include <sys/types.h>
#include <sys/mman.h>
#define FATAL do { fprintf(stderr, "Error at line %d, file %s
(%d) [%s]\n", \
__LINE__, __FILE__, errno, strerror(errno)); exit(1); }
while(0)
#define MAP_SIZE 4096UL
#define MAP_MASK (MAP_SIZE - 1)
int main(int argc, char **argv) {
int fd;
void *map_base = NULL, *virt_addr = NULL;
unsigned long read_result, writeval;
off_t target;
int access_type = 'w';
if(argc...
GIVEN CODE- FILL IN THE
BLANK!
#include <fcntl.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/wait.h>
// Function ptototypes
int readX();
void writeX(int);
int main() /// chi read x ---> divi ---> write x into file
---> par read x --> sub--> write x into file---> chi
read x-->etc
{
int pid;
// pid: used to keep track of the child
process
int x = 19530; // x:
our value as integer
...