a) What molarity of NaOH can be added to a solution of 1.5 x 10-4M Mn(NO3)2,...
a) What molarity of NaOH can be added to a solution of 1.5 x 10-4M Mn(NO3)2, given the Ksp of Mn(OH)2 = 1.6 x 10-13
b) Use equilibrium equations to explain why Cu(Cl)2 is more soluble in a solution of sodium cyanide than in pure water, given that it forms the complex ion Cu(CN)42-.
Homework Answers
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a) What molarity of NaOH can be added to a solution of 1.5 x
10-4M Mn(NO3)2,...
Use equilibrium equations to explain why Cu(Cl)2 is more soluble in a solution of sodium cyanide...
Use equilibrium equations to explain why Cu(Cl)2 is more soluble in a solution of sodium cyanide than in pure water, given that it forms the complex ion Cu(CN)42-.
Will a precipitate form when 100.0mL of 6.6 x 10-4M Mg(NO3)2 is added to 100.0mL of...
Will a precipitate form when 100.0mL of 6.6 x 10-4M Mg(NO3)2 is added to 100.0mL of 1.4x10-4M NaOH? (Ksp for Mg(OH)2 is 8.9x10-12) The ion product for Mg(OH)2 is _____. Since Q is (greater than OR less than) Ksp, Mg(OH)2 (Will OR will not) precipitate from the solution.
Cu(NO3)2 (0.018mol) and NaOH(0.060mol) are added to water to make exactly 1 liter of solution. The...
Cu(NO3)2 (0.018mol) and NaOH(0.060mol) are added to water to make exactly 1 liter of solution. The complex ion that is formed has a tetrahedral geometry. What is the molecular formula of the complex ion formed, and the pH of the solution at equilibrium given that Kf of the complex ion is 1.3x10^16?
yes or no? (References) If a solution is 6.5 x 10- M in Mn (NO3), and...
yes
or no?
(References) If a solution is 6.5 x 10- M in Mn (NO3), and 5.0 x 10 aqueous ammonia, will Mn(OH), precipitate? Min Ksp (Mn(OH)) = 4.6 x 10-14 Kỳ (NH4) =1.8 x 10-5 Yes | Answer Try Another Version tempts remaining No
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x...
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x 10-19), however, it is highly soluble in an ammonia solution due to the formation of the complex ion [Ag(NH3)21 (Kr" 1.7 X 10) Given this information, calculate the molar solubility of AgCl in 2.25 M ammonia. 2. Calculate the molar solubility of Cul in 0.92 M KCN. (Ksp of Cul is 1.1 x 10-12, Kp of [Cu(CN)2] is 1.0 x 1016).
RUESLIon (points) For manganese(II) hydroxide, Mn(OH)2, Ksp = 1.6 x 10-13. Calculate the molar solubility of...
RUESLIon (points) For manganese(II) hydroxide, Mn(OH)2, Ksp = 1.6 x 10-13. Calculate the molar solubility of Mn(OH)2 in a solution that contains 0.158 M NaOH. (Hint: this involves calculating the effect of a common ion on solubility.)
What is the molarity of a solution of sodium phosphate that is made by dissolving 13...
What is the molarity of a solution of sodium phosphate that is made by dissolving 13 g of the solid in 500.0mL of water? A. 1.5 x 10-1M B. 7.9 x 10-2M C. 1.6 x 10-4M D. 0.22 M E. 0.15M
5. A solution is made by mixing 200.0 ml of 1.5 x 10-4 M Cu(NO3)(aq) with...
5. A solution is made by mixing 200.0 ml of 1.5 x 10-4 M Cu(NO3)(aq) with 250.0 ml of 0.20 M NH3(aq). Calculate the concentration of copper ion (Cu? (aq)) in the solution when it reaches equilibrium. (Kr for [Cu(NH3)4]2+ = 1.7 x 1013)
A solution is made 1.1 x 10-3 M in Zn(NO3)2 and 0.150M in NH3. After thw...
A solution is made 1.1 x 10-3 M in Zn(NO3)2 and
0.150M in NH3. After thw solution reaches equilibrium, what
concentration of Zn2+ (aq) remains? Look up the values
of Kf in your book on page 779 (Table 17.3).
Complex Ion K Complex Ion K 1.7 x 1013 Ag(CN)2 1 X 1021 Cu(NH3)4 Ag(NH3)2+ 1.7 x 107 1.5 x 1035 Fe(CN)64 Fe(CN)63 Ag(S203)23 2.8 x 1013 2 x 1043 AIF 3 7 x 1019 Hg(CN). 1.8 X 1041 Al(OH)4 3...
question 17 & 18 Q17. A 5.0 x 10-M solution of Mn is gradually made more...
question 17 & 18
Q17. A 5.0 x 10-M solution of Mn is gradually made more basic by adding NaOH. At what pH will manganese(II) hydroxide begin to precipitate? For Mn(OH)2. Kip - 2.0 x 10-13 Q18. A solution is 0.010 M in each of Pb(NO3)2. Mn(NO3). and Zn(NO3)2. Solid NaOH is added until the pH of the solution is 8.50. Which of these three metal ion(s) will precipitate as a hydroxide? Salt KR Pb(OH)2 1.4 x 10-20 Mn(OH)2 Zn(OH)2...
yes
or no?
(References) If a solution is 6.5 x 10- M in Mn (NO3), and 5.0 x 10 aqueous ammonia, will Mn(OH), precipitate? Min Ksp (Mn(OH)) = 4.6 x 10-14 Kỳ (NH4) =1.8 x 10-5 Yes | Answer Try Another Version tempts remaining No
H. Complex Ions 1. Silver chloride has very low solubility in water (Ks of 1.6 x 10-19), however, it is highly soluble in an ammonia solution due to the formation of the complex ion [Ag(NH3)21 (Kr" 1.7 X 10) Given this information, calculate the molar solubility of AgCl in 2.25 M ammonia. 2. Calculate the molar solubility of Cul in 0.92 M KCN. (Ksp of Cul is 1.1 x 10-12, Kp of [Cu(CN)2] is 1.0 x 1016).
RUESLIon (points) For manganese(II) hydroxide, Mn(OH)2, Ksp = 1.6 x 10-13. Calculate the molar solubility of Mn(OH)2 in a solution that contains 0.158 M NaOH. (Hint: this involves calculating the effect of a common ion on solubility.)
5. A solution is made by mixing 200.0 ml of 1.5 x 10-4 M Cu(NO3)(aq) with 250.0 ml of 0.20 M NH3(aq). Calculate the concentration of copper ion (Cu? (aq)) in the solution when it reaches equilibrium. (Kr for [Cu(NH3)4]2+ = 1.7 x 1013)
A solution is made 1.1 x 10-3 M in Zn(NO3)2 and
0.150M in NH3. After thw solution reaches equilibrium, what
concentration of Zn2+ (aq) remains? Look up the values
of Kf in your book on page 779 (Table 17.3).
Complex Ion K Complex Ion K 1.7 x 1013 Ag(CN)2 1 X 1021 Cu(NH3)4 Ag(NH3)2+ 1.7 x 107 1.5 x 1035 Fe(CN)64 Fe(CN)63 Ag(S203)23 2.8 x 1013 2 x 1043 AIF 3 7 x 1019 Hg(CN). 1.8 X 1041 Al(OH)4 3...
question 17 & 18
Q17. A 5.0 x 10-M solution of Mn is gradually made more basic by adding NaOH. At what pH will manganese(II) hydroxide begin to precipitate? For Mn(OH)2. Kip - 2.0 x 10-13 Q18. A solution is 0.010 M in each of Pb(NO3)2. Mn(NO3). and Zn(NO3)2. Solid NaOH is added until the pH of the solution is 8.50. Which of these three metal ion(s) will precipitate as a hydroxide? Salt KR Pb(OH)2 1.4 x 10-20 Mn(OH)2 Zn(OH)2...
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