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For the reaction of Pt(NH3)2Cl2 + H2O --> Pt(NH3)2(H2O)Cl+ + Cl- the rate law was given...

For the reaction of

Pt(NH3)2Cl2 + H2O --> Pt(NH3)2(H2O)Cl+ + Cl-

the rate law was given as rate=k[Pt(NH3)2Cl2] with k=0.090hr-1. Calculate the initial rate of reaction when the concentration of Pt(NH3)2Cl2 is

(i) 0.010M

(ii) 0.020M

(iii) 0.040M

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