Question

Does anyone knows how to convert 99% confidence interval to 95% if only sample size is known?

Answer 1

Ans:

99% CI for true mean

=sample mean+/-2.576*(s/sqrt(n))

First,find margin of error by calculating (UL-LL)/2

Then divide it by critical z value,it will give us standard error of mean.

Now,if sample size is different for 95% CI,then multiply it by sqrt(n) to get standard deviation.

Now,we know standard deviation and n,use 1.96 critical value for 95% CI and calculate margin of error for 95% CI.