Question

A 2 kg ice puck, moving east with a speed of 3m/s has a head-on collision with a 1.2 kg puck initially at rest. What is the speed of the 2 kg puck after the collision??

Answer 1

Mass of the first puck=m1=2kg

Mass of the second puck=m2=1.2kg

Velocity of the first puck before collision= v1=3m/s

Velocity of the second puck before collision = v2=0m/s

Velocity of the first puck after collision= v1’

For head-on collision use equation,

v1’=[(m1-m2)/(m1+m2)]*v1

Plug values,

v1’=[(2kg-1.2kg)/(2kg+1.2kg)]*(3m/s)

v1’=0.75m/s