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A 0.465-kg hockey puck, moving east with a speed of 3.05 m/s, has a head-on collision...

A 0.465-kg hockey puck, moving east with a speed of 3.05 m/s, has a head-on collision with a 0.900-kg puck initially at rest.

a) Assuming a perfectly elastic collision, what will be the speed (magnitude of the velocity) of each object after the collision?

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Answer #1

Va = [(mA - mB)/(mA + mB)] u

Va = [(0.465 - 0.9)/(0.465 + 0.9)] x 3.05

Va = 0.97 m/s

Vb = [(2 mA)/(mA + mB)] u

Vb = [(2 x 0.465)/(0.465 + 0.9)] x 3.05

Vb = 2.08 m/s

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