x P(x) 0 0.01639 1 0.18033 2 0.22951 3 0.26230 4 0.03279 5 0.18033 6 0.01639...
x P(x)
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0 0.01639
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1 0.18033
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2 0.22951
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3 0.26230
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4 0.03279
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5 0.18033
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6 0.01639
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7 0.01639
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8 0.01639
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9 0.03279
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10 0.01639
Using the same probability distribution given in problem 1, would it be unusual for one of my 2019 M146 students to have 8 or more siblings?
Homework Answers
P(8 or more siblings) = 0.01639 + 0.03279 + 0.01639 = 0.06557
Hence,
No, it would not be unusual for one of M146 students to have 8 or more siblings because the probability is greater than 0.05.
Add Answer to:
x P(x)
0 0.01639
1 0.18033
2 0.22951
3 0.26230
4 0.03279
5 0.18033
6 0.01639...
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