A preliminary survey shows that 31% of college students smoke. In a class of 40 students,...
A preliminary survey shows that 31% of college students smoke. In a class of 40 students, what is the probability that more than 46% of the students smoke? Use Appendix B.1 for the z-values. (Round the z-value to 2 decimal places and the final answer to 4 decimal places.)
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A preliminary survey shows that 31% of college students smoke.
In a class of 40 students,...
A preliminary survey shows that 34% of college students smoke. In a class of 37 students,...
A preliminary survey shows that 34% of college students smoke. In a class of 37 students, what is the probability that more than 49% of the students smoke? Use Appendix B.1 for the z-values. (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability ??
A preliminary survey shows that 32% of college students smoke. In a class of 36 students,...
A preliminary survey shows that 32% of college students smoke. In a class of 36 students, what is the probability that more than 47% of the students smoke? Use Appendix B.1 for the z-values. (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability
construct a sampling distribution of a proportion
A preliminary survey shows that 20% of college students smoke. In a class of 35 students, what is the probability that more than 35% of the students smoke? Use Appendix B.1 for the z-values. (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability =
A selective college would like to have an entering class of 1000 students. Because not all...
A selective college would like to have an entering class of 1000 students. Because not all students who are offered admission accept, the college admits more than 1000 students. Past experience shows that about 83% of the students admitted will accept. The college decides to admit 1200 students. Assuming that students make their decisions independently, the number who accept has the B(1200, 0.83) distribution. If this number is less than 1000, the college will admit students from its waiting list....
The average American gets a haircut every 40 days. Is the average different for college students?...
The average American gets a haircut every 40 days. Is the average different for college students? The data below shows the results of a survey of 16 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 40, 40, 46, 40, 31, 46, 34, 44, 34, 42, 36, 27, 37, 46, 40, 37 What can be concluded at the the α α = 0.10 level of significance level of significance? For...
suppose that 50% of all college students smoke cigarettes. a sample of 12 is selected randomly....
suppose that 50% of all college students smoke cigarettes. a sample of 12 is selected randomly. what is the probability that between 6 and 10 (both inclusive) students smoke? round your answer to four decimal places.
Suppose that 30% of all college students smoke cigarettes. A sample of 16 is selected randomly....
Suppose that 30% of all college students smoke cigarettes. A sample of 16 is selected randomly. . What is the probability that between 5 and 8 (both inclusive) students smoke? Round your answer to four decimal places.
Suppose that 30% of all college students smoke cigarettes. A sample of 14 is selected randomly....
Suppose that 30% of all college students smoke cigarettes. A sample of 14 is selected randomly. What is the probability that between 6 and 8 (both inclusive) students smoke? Round your answer to four decimal places.
The time needed to complete a final examination in a particular college course is normally distributed...
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes and a standard deviation of 12 minutes. Answer the following questions. Round the intermediate calculations for z value to 2 decimal places. Use Table 1 in Appendix B a. What is the probability of completing the exam in one hour or less (to 4 decimals)? b. What is the probability that a student will complete the exam in...
A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at h...
A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at home Complete parts a through d below 2009. A sample of 150 college students was selected. a. Calculate the standard error of the proportion. (Round to four decimal places as needed.) b. What is the probability that less than 40% of the college students from the sample spent their spring breaks relaxing at home? P(Less than 40% of the college students...
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes and a standard deviation of 12 minutes. Answer the following questions. Round the intermediate calculations for z value to 2 decimal places. Use Table 1 in Appendix B a. What is the probability of completing the exam in one hour or less (to 4 decimals)? b. What is the probability that a student will complete the exam in...
A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at home Complete parts a through d below 2009. A sample of 150 college students was selected. a. Calculate the standard error of the proportion. (Round to four decimal places as needed.) b. What is the probability that less than 40% of the college students from the sample spent their spring breaks relaxing at home? P(Less than 40% of the college students...
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