Question

This works as expected BUT when I enter a input that is incorrect more than one time, the second time it stops works.

It works as expected and redisplays the prompt after the first time an exception is raised but crashes the second. Any help appreciated!

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# This program will open and read a list of numbers in a text file and then terminate

def nums():
  
prompt = input("Please enter the name of your file: ")
  
  read_numbers = prompt
# This is the variable that keeps track of the text file

numbersInput = open(read_numbers, 'r')
# References the variable 'read_numbers' to open the text file

numString = numbersInput.read()
# references the variable 'numbersInput' and reads the text file

print(numString)
# Prints the contents of the text file to the shell

numbersInput.close()
# Closes the text file

def main():
try:
nums()
except FileNotFoundError:
print("This file is not available!",'\n')
nums()
except:
print("There has been an error!",'\n')
nums()

main()

Answer 1

The answer to this question is as follows:

The code is as follows:

def nums():
prompt = input("Please enter the name of your file: ")
read_numbers = prompt
numbersInput = open(read_numbers, 'r')
numString = numbersInput.read()
print(numString)
numbersInput.close()
def main():
while True:
try:
nums()
except FileNotFoundError:
print("This file is not available!",'\n')
except:
print("There has been an error!",'\n')
nums()

main()

The input and output are provided in the screenshot below: