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Please help calculate kab for the reaction A2-+B3- --> A3- + B2- for self exchange of...

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calculate kab for the reaction A2-+B3- --> A3- + B2-

for self exchange of A Eo=0.68V and kaa =7.4x102

for self exchange of B E0=0.54V and kbb=7x104

E0cell=Eocathode-EoAnode

K12=e-(-nFEcell/RT) F=96500

use marcus relationship kab=(kabkbbKab)1/2

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