Fusion problems, find the energy release
Solution:
a) 2H +3H → 4He + 1n
E =
mc2
= [4.00260 + 1.007825- 3.01605 - 2.014102 ]*931.5
= - 18.4 MeV
b) 4He +4He → 7Be + 1n
E =
mc2
= [7.01692872 + 1.007825- 2*4.00260 ]*931.5
= 18.2 MeV .
c) 2H +3He → 4He + 1n
E =
mc2
= [4.00260 + 1.007825- 3.01605 - 2.014102 ]*931.5
= -18.4 MeV .
d) 2H + 1H → ᵞ+ 3H
E =
mc2
= [3.01605 - 2.014102 - 1.007825]*931.5
= -5.5 MeV.
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Fusion problems, find the energy release 2H +3H → 4He + ? 4He +4He → 7Be...
Complete the following fusion process: 1H+2H⟶−−−−−− Complete the following fusion process: 31n 4He 3He 1n
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Find the energy Q released in the fusion reaction. (Note that the reaction below is between nuclei. For the atomic masses, see this table. The mass of an electron is 0.00054 1H+3He → 4He + e+ + ν MeV
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