Question

1. Consider the Fusion reaction 3H +3H -> 4He + 2 n How much energy is...

1. Consider the Fusion reaction 3H +3H -> 4He + 2 n How much energy is released (in MeV)?

2. How much energy is released in the fission reaction below (in MeV)?

n + 239Pu -> 135Xe + 102Ru + 3n

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Answer #1

1 )

given

3H + 3H ----> 4He + 2 n

LHS = RHS

the mass of the 3H is = 3.0160493 u

the mass of the 4He is = 4.0026032 u

the mass of the neutron is " n " = 1.0086649 u

2n = 2.0173298 u

LHS = 3.0160493 u + 3.0160493 u

= 6.0320986 u

RHS = 4.0026032 u + 2.0173298 u

= 6.019933 u

the difference in the masse is m = 6.0320986 u - 6.019933 u

m = 0.0121656 u

the energy is released is E = m x 931.5

= 0.0121656 x 931.5

so the energy released is E = 11.3322564 MeV

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