Suppose that 17 percent of an extremely large population are smokers. Six people are randomly selected. Answer the following questions, rounding your answers to two decimal places. (a) What is the probability that no more than two of these people are smokers? (b) What is the probability that there is at least one smoker in the group of six?
We are given percentage and sample size, so we have to find this
using binomial probability rule.
Suppose that 17 percent of an extremely large population are smokers. Six people are randomly selected....
In a large population, 53% of the people have been vaccinated. If 5 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated? Give your answer as a decimal to 4 places.
4 percent of a certain company's life insurance policy holders are smokers. For each nonsmoker the probability of dying during the year is 0.011. For each smoker the probability of dying during the year is 0.04. Round your answers to at least 4 decimal places. [a]Find the probability that a randomly selected policyholder died last year. [b]Find the probability that a randomly selected policy holder who died last year was a smoker.
In a large population, 68 % of the people have been vaccinated. If 3 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated? Give your answer as a decimal (to at least 3 places) or fraction.
About 12% of the population of a large country is nervous around strangers. If two people are randomly selected, what is the probability both are nervous around strangers? What is the probability at least one is nervous around strangers? (a) The probability that both will be nervous around strangers is (Round to four decimal places as needed) (b) The probability that at least one person is nervous around strangers is (Round to four decimal places as needed.)
Could someone please explain the steps and logic used to solve
this problem?
Here are the answers, I just need help with how to get
there.
a) 0.03087
b) 0.3087
c) 0.07203
d) 0.16807
e) 0.50
f) 0.293
2. Suppose you sample people randomly from a very large population, and in this population 30% of them are smokers. Assume for parts a-d that the population is so large that we may treat the sampling as though it were sampling with...
In a region, 80% of the population have brown eyes. If 15 people are randomly selected, find the probability that at least 13 of them have brown eyes. Is it unusual to randomly select 15 people and find that at least 13 of them have brown eyes? Why or why not? The probability that at least 13 of the 15 people selected have brown eyes is (Round to three decimal places as needed.)
The average amount of money that people spend at Don Mcalds fast food place is $7.7600 with a standard deviation of $1.5100. 6 customers are randomly selected. Please answer the following questions, and round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of ¯ x ? ¯ x ~ N= What is the distribution of ∑ x ? ∑ x ~ N= What is the probability that one randomly selected customer...
Suppose that 905 smokers each
received a nicotine patch, which delivers nicotine to the
bloodstream at a much slower rate than cigarettes do. Dosage was
decreased to 0 over a 12 week period. Of these 905 people, 255 were
still not smoking 6 months after treatment. Assume this sample is
representative of all smokers.
Suppose that 905 smokers each received a nicotine patch, which delivers nicotine to the bloodstream at a much slower rate than cigarettes do. Dosage was decreased...
About 19% of the population of a large country is nervous around strangers. If two people are randomly selected, what is the probability both are nervous around strangers? What is the probability at least one is nervous around strangers? (a) The probability that both will be nervous around strangers is
please kindly make solution and answers visible. thanks
The average amount of money that people spend at Don Mcalds fast food place is $7.6500 with a standard deviation of $1.8200. 17 customers are randomly selected. Please answer the following questions, and round all answers to 4 decimal places where possible and assume a normal distribution. a. What is the distribution of X? X-NI b. What is the distribution of ? -NE c. What is the distribution of +?\--N d. What...