8.3
4) the claim is that for 12 am body temperature the mean is
>98.6 degrees Fahrenheit. the sample size is n= 7 and the test
statistic is t= 1.649. round to 3 decimal places as needed.
p value =_______
Degrees of freedom = n - 1 = 7 - 1 = 6
Hence,
p - Value = P(t6 > 1.649) = 0.075
8.3 4) the claim is that for 12 am body temperature the mean is >98.6 degrees...
The claim is that for 12 am body temperatures, the mean is 98.6 degrees, the sample size is 6 and the test statistic is -1.121. What is the P-value?
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is h> 98.6°F. The sample size is n = 7 and the test statistic is t= 1.768. P-value = (Round to three decimal places as needed.)
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is p > 98.6°F. The sample size is n = 4 and the test statistic is t= 2.676. P-value = (Round to three decimal places as needed.)
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is μ>98.6°F. The sample size is n=9 and the test statistic is t=2.657. P-value= (Round to three decimal places as needed.)
It has long been stated that the mean temperature of humans is
98.6 degrees°F. However, two researchers currently involved in the
subject thought that the mean temperature of humans is less than
98.6 degrees°F. They measured the temperatures of 50 healthy adults
1 to 4 times daily for 3 days, obtaining 225 measurements. The
sample data resulted in a sample mean of 98.3 degrees°F and a
sample standard deviation of 11 degrees°F. Use the P-value
approach to conduct a hypothesis...
The claim is that for 12 AM body temperatures, the mean is mugreater than98.6degreesF. The sample size is n=7 and the test statistic is t=2.377.
Next Question Use technology to find the P-value for the hypothesis test described below The claim is that for 12 AM body temperatures, the mean is > 98.6°F. The sample size is n-6 and the test statistic ist=2,585 P-value (Round to three decimal places as needed.)
Human body temperature is 98.6 degrees, a nurse thinks this is too high, that is the mean body temperature is below 98.6. The nurse obtains a random sample of 106 human body temperatures and finds that the mean for the sample is 98.20 degrees; she assumes the population standard deviation is 0.62 degrees. At an alpha=0.02 test the nurse's claim.
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is μ>98.6 degrees°F. The sample size is n=3 and the test statistic is t=1.027. using statcrunch walk through
In a sample of 40 adults, the mean body temperature was 98.305 degrees Fahrenheit with a standard deviation of 0.766 degrees Fahrenheit. Part A Construct a 90% confidence interval to estimate the mean body temperature in the population. Show all of your work using the Canvas equation editor and round your final answer to three decimal places. Hints S E = s n = 0.766 40 = 0.121 The t* multiplier for a 90% interval with 39 degrees of freedom...