Ethyl alcohol has a boiling point of 78.0 degrees Celsius, a freezing point of -114 degrees Celsius, a latent heat of vaporization of 879 kJ/K, a latent heat of fusion of 109 kJ/K, and a specific heat of 2.43 kJ/kg.K. How much energy must be removed from 0.510 kg of ethyl alcohol that is initially a gas at 78.0 degrees Celsius so that it becomes a solid at -114 degrees Celsius?
here,
the mass of ethyl alcohol , m = 0.51 kg
initial temperature , Ti = 78 degree C
the final temperature , Tf = - 114 degree C
the heat energy required , Q = m * ( Lv + Ce * ( Ti - Tf) + Lf)
Q = 0.51 * ( 879 + 2.43 * ( 78 - (-114) + 109 ) KJ
Q = 742 KJ
Ethyl alcohol has a boiling point of 78.0 degrees Celsius, a freezing point of -114 degrees...
Ethyl alcohol has a boiling point of 78.0 ˚C, a freezing point of -114 ˚C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg·K. How much energy must be removed from 0.689 kg of ethyl alcohol that is initially a gas at 78.0 ˚C so that it becomes a solid at -114 ˚C?
Ethyl alcohol has a boiling point of 78.0 ˚C, a freezing point of -114 ˚C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg·K. How much energy must be removed from 0.683 kg of ethyl alcohol that is initially a gas at 78.0 ˚C so that it becomes a solid at -114 ˚C?
Ethyl alcohol has a boiling point of 78.0 degree C, a freezing point of -114 degree C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg-K. How much energy must be removed from 0.567 kg of ethyl alcohol that is initially a gas at 78.0 degree C so that it becomes a solid at -114 degree C?
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