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The equilibrium constant in terms of pressures for the reduction of tungsten(IV) oxide to tungsten at...

The equilibrium constant in terms of pressures for the reduction of tungsten(IV) oxide to tungsten at 25 °C is Kp = 3.82×10-4, corresponding to the reaction

WO2(s) + 2CO(g) <--> W(s) + 2CO2(g)

If the total pressure of an equilibrium system at 25 °C is 2.82 atm, calculate the partial pressures of CO(g) and CO2(g).

PCO = _____atm

PCO2 = ______atm

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