For each example below you would start to construct a confidence interval by identifying which distribution should be used to find the margin of error. It is possible that you won't be able to use either distribution.
(a) a confidence interval for a population proportion where n = 66 and there are 63 successes in your sample leading to a sample proportion of 0.955
A. z-distribution
B. t-distribution
C. neither distribution
(b) a confidence interval for a population proportion where
n = 39 and there are 29 successes in your sample leading
to a sample proportion of 0.744
A. z-distribution
B. T-distribution
C. neither distribution
Solution:
a)
We use Z - distribution
A) z-distribution
Option A is correct.
b)
A. z-distribution
Option A is correct.
For each example below you would start to construct a confidence interval by identifying which distribution...
For each example below you would start to construct a confidence interval by identifying which distribution should be used to find the margin of error. It is possible that you won't be able to use either distribution. (a) a confidence interval for a population proportion where n = 61 and there are 37 successes in your sample leading to a sample proportion of 0.607 z-distribution t-distribution neither distribution (b) a confidence interval for a population proportion where n = 38...
When to Use What: For each example below you would start to construct a confidence interval by identifying which distribution should be used to find the margin of error. It is possible that you won't be able to use either distribution. (a) a confidence interval for a population proportion where n = 45 and there are 27 successes in your sample leading to a sample proportion of 0.600 t-distribution z-distribution neither distribution
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 14 mortgage institutions, the mean interest rate was 3.44% and the standard deviation was 0.49%. Assume the interest rates are normally distributed. Which distribution should be used to construct the confidence interval? select a choice below A. Use a t-distribution because the interest...
Use the standard normal distribution or the t-distribution to construct the indicated confidence interval for the population mean of each data set. Justify your decision. If neither distribution can be used, explain why. Interpret the results. (a) In a random sample of 36 patients, the mean waiting time at a dentist’s office was 24 minutes and the standard deviation was 7.5 minutes. Construct a 90% confidence interval for the population mean. (b) In a random sample of 25 cereal boxes,...
Use the standard nomal distribution or the distribution to construct a 95% confidence interval for the population mean. Justily your decisioni neither distribution can be used, explain why. Interpret the results In a random sample of 41 people, the mean body mass index (BMI) was 27.8 and the standard deviation was 6.11 Which distribution should be used to construct the confidence interval? Choose the correct answer below. O A Use a distribution because the sample is random, na 30, and...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 48 people, the mean body mass index (BMI) was 26.1 and the standard deviation was 6.06. Which distribution should be used to construct the confidence interval? Choose the correct answer below.
Use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 13 people, the mean length of stay at a hospital was 6.9 days. Assume the population standard deviation is 2.1 days and the lengths of stay are normally distributed. Which distribution should be used to construct the confidence interval? A. Use a normal...