Question

The heights of smart clones are distributed approximations normally with mean of 5.6 feet and standard...

The heights of smart clones are distributed approximations normally with mean of 5.6 feet and standard deviation of 0.0130 feet. Let X be the night of a randomly selected clone. Find the probability that: a) x is less than 5.6186 feet b) x is greater than 5.58824 feet c) x and sits eman differ by less than 1.5 standard variations d) find c such that between 5.6-c and 5.6+c is included in 98% of the clones heights

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer

Find the probability that:

a) x is less than 5.6186 feet

P(X<5.6186) = P(Z< (5.6186-5.6)/.013 ) = P(Z<1.431) = .924

b) x is greater than 5.58824 feet = P(X>5.58824) = P(Z> -.90462) = .1828

c) x and sits eman differ by less than 1.5 standard variations = P(|X-x| < 1.5*Stdev) = P(-1.5<Z<1.5) = .8664

d) find c such that between 5.6-c and 5.6+c is included in 98% of the clones heights?

So, P(X< 5.6-c) = .01 ( 100-98%)/2 = 1%)

So, ((5.6-c) - 5.6)/.013 = -2.33

c = .03024

So, value of c is .03024

Add a comment
Know the answer?
Add Answer to:
The heights of smart clones are distributed approximations normally with mean of 5.6 feet and standard...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Assume men's heights are normally distributed with mean 69.5 in. and standard deviation 2.4 in. If...

    Assume men's heights are normally distributed with mean 69.5 in. and standard deviation 2.4 in. If you randomly selected a man whats the probability that his height would be A. Over 6 feet B. Between 5'9 and 6'4 C. Less than 2 standard deviations above the mean D.What is height that separates the tallest 10% of men from the rest of men? What do we call this value? E. If 25 men were randomly selected what is the probability that...

  • Assume that​ women's heights are normally distributed with a mean given by μ=62.2 in​,and a standard...

    Assume that​ women's heights are normally distributed with a mean given by μ=62.2 in​,and a standard deviation given by σ=2.8 in. ​(a) If 1 woman is randomly​ selected, find the probability that her height is less than 63 in. ​(b) If 35 women are randomly​ selected, find the probability that they have a mean height less than 63 in.

  • The heights of pecan trees are normally distributed with a mean of 10 feet and a...

    The heights of pecan trees are normally distributed with a mean of 10 feet and a standard deviation of 2 feet. Show all work. Just the answer, without supporting work, will receive no credit. (a) What is the probability that a randomly selected pecan tree is between 9 and 12 feet tall? (Round the answer to 4 decimal places) (b) Find the 80th percentile of the pecan tree height distribution. (Round the answer to 2 decimal places) (a) For a...

  • The heights of pecan trees are normally distributed with a mean of 10 feet and a...

    The heights of pecan trees are normally distributed with a mean of 10 feet and a standard deviation of 2 feet. Show all work. Just the answer, without supporting work, will receive no credit. (a) What is the probability that a randomly selected pecan tree is between 8 and 13 feet tall? (round the answer to 4 decimal places) (b) Find the 80th percentile of the pecan tree height distribution. (round the answer to 2 decimal places) (c) To get...

  • Basketball player heights are normally distributed with a mean of 195 cm. and a standard deviation...

    Basketball player heights are normally distributed with a mean of 195 cm. and a standard deviation of 20 cm. What is the probability that a randomly selected player's height is less than 180 cm? Show your work.

  • Assume that​ women's heights are normally distributed with a mean given by mu equals 63.5 in​,...

    Assume that​ women's heights are normally distributed with a mean given by mu equals 63.5 in​, and a standard deviation given by sigma equals 2.6 in. ​(a) If 1 woman is randomly​ selected, find the probability that her height is less than 64 in. ​(b) If 44 women are randomly​ selected, find the probability that they have a mean height less than 64 in.

  • Suppose that the battery life on the New Smart Phone is approximately normally distributed with mean...

    Suppose that the battery life on the New Smart Phone is approximately normally distributed with mean 5.6 hours and standard deviation 0.62 hour. What is the probability that a fully charged New Smart Phone will last less than 5.02 hours? My options are- .2134 -.216 .1748 .8252

  • Assume that women's heights are normally distributed with a mean given by = 63.4 in, and...

    Assume that women's heights are normally distributed with a mean given by = 63.4 in, and a standard deviation given by o =2.7 in. (a) ir 1 woman is randomly selected, find the probability that her height is less than 64 in (b) If 49 women are randomly selected, find the probability that they have a mean height less than 64 in. (a) The probability is approximately (Round to four decimal places as needed.) (b) The probability is approximately (Round...

  • Assume that women’s heights are normally distributed with a mean given by µ = 63.5 in,...

    Assume that women’s heights are normally distributed with a mean given by µ = 63.5 in, and a standard deviation given by σ = 2.9 in. If 1 woman is randomly selected, find the probability that her height is less than 61 in. Round to four decimal places and leave as a decimal If 70 women are randomly selected, find the probability that they have a mean height less than 64 in. Round to four decimal places and leave as...

  • Woman’s heights are normally distributed with a mean of 63.8 inches and standard deviation of 2.3...

    Woman’s heights are normally distributed with a mean of 63.8 inches and standard deviation of 2.3 inches. Find �)*. This would be the height which about 85% of woman are less than and 15% of woman are greater than.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT