Suppose that the battery life on the New Smart Phone is approximately normally distributed with mean 5.6 hours and standard deviation 0.62 hour.
What is the probability that a fully charged New Smart Phone will last less than 5.02 hours?
My options are-
.2134
-.216
.1748
.8252
Solution :
Given that ,
mean = = 5.6
standard deviation = = 0.62
P(x < 5.02 ) = P[(x - ) / < (5.02 - 5.6) / 0.62 ]
= P(z < -0.9355 )
= 0.1748 , Probability = 0.1748
Option 3rd is correct.
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