Prepare 0.25M NaOH in 350ml (MW NaOH=40g); How about 0.1N NaOH?
Please show work
To make 0.25 M NaOH, you need to find out the required mass of NaOH.
Molarity = (given mass / molecular mass) × (1 / volume in litres)
0.25 = (given mass / 40) × (1000 / 350)
Given mass = 0.25 × 40 × 350 / 1000 = 3500 / 1000 = 3.5 g
So, you require 3.5 g NaOH to make 350 ml, 0.25 M of it.
For 0.1 N NaOH,
0.1 N = 0.1 M NaOH, it is because,
normality = n factor × molarity
n factor for NaOH is 1.
So, you need to prepare 0.1 M NaOH.
0.1 = (given mass / 40) × (1000 / 350)
Given mass = 0.1 × 40 × 350 / 1000 = 1.4 g
So, you require 1.4 g of NaOH to make 0.25 M, 350 ml of it.
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Prepare 0.25M NaOH in 350ml (MW NaOH=40g); How about 0.1N NaOH? Please show work
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