Question

In Java write a program for a “calculator” that performs any conversion between decimal / binary / hexadecimal values that are provided as inputs by the user.

Answer 1

SOURCE CODE:

*Please follow the comments to better understand the code.

**Please look at the Screenshot below and use this code to copy-paste.

***The code in the below screenshot is neatly indented for better understanding.

import java.util.Scanner;
class Main
{
   public static void main (String[] args)
   {
   Scanner sc= new Scanner(System.in);
  
   //Menu
   System.out.println("1. Decimal To Binary ");
   System.out.println("2. Decimal To Hexadecimal ");
   System.out.println("3. Binary To Decimal ");
   System.out.println("4. Binary To Hexadecimal ");
   System.out.println("5. Hexadecimal To Decimal ");
   System.out.println("6. Hexadecimal To Binary ");
   System.out.println("7. Exit ");
  
   //LOOP through the user choice
   while(true)
   {
   System.out.print("Choose the option: ");
   int choice = sc.nextInt();
   if(choice==7)
   break;
   System.out.print("Enter Number: ");
   String num;
   int n;
   switch(choice)
   {
   case 1: num=sc.next();
   n=Integer.parseInt(num,10);
   System.out.println("The Binary Form is : "+Integer.toBinaryString(n));
   break;
   case 2: num=sc.next();
   n=Integer.parseInt(num,10);
   System.out.println("The Hexadecimal Form is : "+Integer.toHexString(n));
   break;
  
   case 3: num=sc.next();
   n=Integer.parseInt(num,2);
   System.out.println("The Decimal Form is : "+n);
   break;
  
   case 4: num=sc.next();
   n=Integer.parseInt(num,2);
   System.out.println("The Hexadecimal Form is : "+Integer.toHexString(n));
   break;
  
   case 5: num=sc.next();
   n=Integer.parseInt(num,16);
   System.out.println("The Decimal Form is : "+n);
   break;
  
   case 6: num=sc.next();
   n=Integer.parseInt(num,16);
   System.out.println("The Binary Form is : "+Integer.toBinaryString(n));
   break;
   default: break;
   }
   }
   }
}

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SCREENSHOT:

OUTPUT: