A 6.15 kg block is pulled by a rope up a ramp with an incline of 25 degrees from the horizontal. The acceleration of the block is 2.45 m/s^2. The coefficient of friction between the block and the ramp is 0.266. What is the tension in the rope?
Fnet = FT - m*g*sin(25) - μ*k*m*g*cos(25)
m*a = FT - m*g*sin(25) - μ*k*m*g*cos(25)
FT = m*(a + g*sin(25) + μ*k*g*cos(25))
= 6.15*(2.45 + 9.81*sin(25) + 0.266*9.81*cos(25))
= 55.11 N
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a) what was the acceleration of the block down the ramp before
the rope is pulled?
b) what was the acceleration of the block down the ramp after
the rope is pulled?
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