Question

Let S = {−1, 0, 2, 4, 7}, find f(S) if 1. f(x) = 1 2....

Let S = {−1, 0, 2, 4, 7}, find f(S) if

1. f(x) = 1

2. f(x) = 2x + 1

3. f(x) = bx/5c

4. f(x) = d(x 2 + 1)/3e

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Answer #1

1. f(x) = 1

Explanation: Output is 1 irrespective of of the value of x.

2. f(x) = 2x+1

Explanation: Put each value in set and evaluate.

x = -1 --> 2 * ( - 1 ) + 1 --> - 2 + 1 --> -1

x = 0 --> 2 * ( 0 ) + 1 --> 0 + 1 and so on for other values in S.

3. f(x) = bx/5c

Explanation : Here b and c are contant values as will be provided.

x = -1 --> b * (-1) / 5c --> -b / 5c

x = 0 --> b * (0) /5c --> 0 and so on for other values.

4. f(x) = d(x^2+1)/3e

Explanation : Here d and e are contant values.

x = -1 --> d ( (-1)^2 +1 ) / 3e --> d( 1 + 1) / 3e --> 2d/3e and so on for other values.

The table for all the values in S is as shown below along with mapping as per f(x).

x; x E S f(x) = 1 f(x) = 2x + 1 f(x) = bx/5c f(x) = d(x^2 + 1)/3e
-1 1 -1 -b/5c 2d/3e
0 1 1 0 d/3e
2 1 5 2b/5c 5d/3e
4 1 9 4b/5c 17d/3e
7 1 15 7b/5c 50d/3e
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