Question

What mass in gram NaN3 is required to produce 50.2 L of N2 gas (density = 1.25 g/L ) according to the balanced chemical reaction: 2 NaN₃(s) →2 Na(s) + 3N₂(g)

Answer 1

2 NaN₃(s) →2 Na(s) + 3N₂(g)
given
50.2 L of N2 gas
density = 1.25 g/L
mass = volume * density = 1.25 g/l * 50.2 l
= 62.75 g

molar mass of N2 = 28.01 g/mol

number of moles of N2 produced = 62.75 g/28.01 g/mol
= 2.24027 mols

mol ratio N2 : NaN3 = 3:2

mols of NaN3 needed = [2/3]* 2.24027 mols = 1.4935 mols

molar mass of NaN3 = 65.01 g/mol

mass of naN3 needed = 65.01 g/mol *1.4935 mol = 97.09 g

round to 3 sig.fig.

Answer : Mass of NaN3 = 97.1 g
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