For conduction heat transfer in a constant area fin, efficiency increases with
For conduction, heat transfer in a constant area fin, efficiency increases with decreasing fin length because of the increase in gin temperature with length.
For conduction heat transfer in a constant area fin, efficiency increases with
3.25 For the heat sink shown in the accomping figure, find (a)
the fin efficiency, (b) the surface efficiency, and (c) the heat
transfer from the heat sink.
Heat Sinks 3.25 ure, find (a) the fin efficiency, (b) the surface efficiency, For the heat sink shown in the accompanying fig- and (c) the heat transfer from the heat sink. T,, = 40°C 5 mm h = 16 W/m·K 4 cm 6061 aluminum 12 cm L= 25 cm To 90°C
The heat that is conducted through a body must frequently be removed by other heat transfer processes. For example, the heat generated in an electronic device must be dissipated to the surroundings through convection by means of fins. Consider the one-dimensional aluminum fin (thickness t 3.0 mm, width 20 cm, length L) shown in Figure 1, that is exposed to a surrounding fluid at a temperature T. The conductivity of the aluminum fin (k) and coefficient of heat convection of...
Cooling fins are used to increase the area available for heat
transfer between metal walls and poorly conducting fluids such as
gases. A rectangular fin is shown in the following figure.
To design a cooling fin and calculate the fin efficiency one
must first calculate the temperature profile in the fin.
If L>>B, no heat is lost from the end or from the edges,
and the heat flux at the surface is given by:
in which the convective heat transfer...
Consider two walls, each kept at constant temperature T. and joining them is an aluminum fin of length L. There is internal heat generation q in this fin. Air flows over the fin having convective heat transfer coefficient h and temperature T.. Prove that the efficiency of the fin can be given by tanh (mL/2) mL/2 where m2 P= perimeter of the fin, A = area of the fin cross-section, and k = thermal conductivity of the fin. n =...
Compare the rate of heat conduction through a 12 cm thick wall that has an area of 15 m2 and a thermal conductivity twice that of glass wool, k=0.042, with the rate of heat conduction through a window, k=0.84, that is 0.8 cm thick and that has an area of 2.75 m2, assuming a temperature difference of 12 °C across each. (a) What is the heat transfer rate through the wall? QtQt = unit (b) What is the heat transfer rate...
Considering the cooling process of a circular fin by
means of convective heat transfer along its length (see figure
below), governed by:
d dT where a is a parameter and T is the ambient temperature. The fin has a uniform temperature at the cross-sectional area (in the radial direction). The base (left side) of the fin is at a constant temperature TB of 120° and the top (right side) of the fine is fully insulated. Data: L = 1.0 m,...
The heat that is conducted through a body must frequently be removed by other heat transfer processes. For example, the heat generated in an electronic device must be dissipated to the surroundings through convection by means of fins. Consider the one-dimensional aluminum fin (thickness t = 3.0 mm, width Z = 20 cm, length L) shown in Figure 1, that is exposed to a surrounding fluid at a temperature T. The conductivity of the aluminum fin (k) and coefficient of...
Assuming the rate of heat transfer to be correctly modeled with an adiabatic fin tip BC, what is the % error if the rate of heat transfer is determined using an infinitely long fin BC? The cylindrical fin measures 20 cm long and has a radius of 0.15 cm. Take k = 200 W/m·K and h = 10 W/m2·K.
4. Derive the fin heat transfer rate, qf, in two different ways. Use the long fin approximation. You can use the usual notation learned in the class. (30 pt)