Question

Write a program that generates a sequence of 20 random die tosses in an ArrayList and that prints the die values, marking only the longest run, like this: 1 2 5 5 3 1 2 4 3 (2 2 2 2) 3 6 5 5 6 3 1

If there is more than one run of maximum length, mark the first one.

Must use ArrayList, not an array!

Answer 1

import java.util.ArrayList;
import java.util.Random;

public class Test {
  
  

public static void main(String argv[])
{
ArrayList<Integer> R = new ArrayList<Integer>();
  
Random r = new Random();
  
//generating and storing 20 random die tosses
//and also finding the longest run
int max=1;
int c1=0;
int c2=0;
int i=1;
int p=r.nextInt()%6;//random die value
if(p<0)p=p*-1;
p=p+1;
R.add(p);//adding to arraylist
int k;
int pc1=0,pc2=0;
  
while(i<20)
{
k=r.nextInt()%6;
if(k<0)k=k*-1;
k=k+1;
R.add(k);
if(p==k)//finding longest run
{
pc2=i;
if(max<(pc2-pc1+1))
{
max=pc2-pc1+1;
c1=pc1;
c2=pc2;
}
}
else
{
pc1=i;
}
  
p=k;
  
i++;;
}
  
//displaying output
// System.out.println(R.size());
for(k=0;k<20;k++)
{
if(k==c1)
{
  
System.out.print("("+R.get(k)+" ");
}
else if(k==c2)
System.out.print(R.get(k)+") ");
else
System.out.print(R.get(k)+" ");
}
System.out.println();
}
}

output:

run:
6 5 5 (3 3 3) 6 2 2 6 3 6 5 1 5 1 2 2 6 2
BUILD SUCCESSFUL (total time: 0 seconds)