Question

How many moles of solute are contained in each solution?

250mL of a 0.82M Na NO3

Answer 1

Ans :

Number of moles of solute are given as :

moles = molarity x volume of solution (L)

here molarity is 0.82 M

volume = 250 mL = 0.250 L

So putting values :

moles = 0.82 M x 0.250 L

= 0.205 moles

so 0.205 moles of NaNO3 are present in the solution

Answer 2

To determine the number of moles of solute in a solution, you can use the formula:

moles = concentration (M) × volume (L)

Given: Concentration (M) = 0.82 M Volume (mL) = 250 mL

First, convert the volume from milliliters (mL) to liters (L): Volume (L) = 250 mL ÷ 1000 = 0.250 L

Now we can calculate the number of moles of solute: moles = 0.82 M × 0.250 L = 0.205 mol

Therefore, there are 0.205 moles of NaNO3 in the given solution.