How much solute is required to make 250mL of a 1 molar solution of KCl? Given K= 39.1g Cl=35.45g
Molarity = (W /MW) (1000 / V in mL )
Molarity = 1.0 M
W = ?
MW = 74.55 g /mol
V = 250 mL
1.0 = (W / 74.55) (1000/250)
W / 74.55 = 0.25
W = 18.64 g
mass of solute required = 18.64 g
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