Question

I need help and I'm stuck on this program. I have to do it in the C language on my Linux system. Can someone help me with this please? I have included my instructions and sample output. Thank you

-Initialize 2 arrays within the main method, one with odd numbers and one with even numbers.

-In the main method swap the arrays.

-Print the arrays before and after the swap.

//output should look like the following

Before Swap

firstArray[0] = 0, secondArray[0] = 1

firstArray[1] = 2, secondArray[1] = 3

firstArray[2] = 4, secondArray[2] = 5

firstArray[3] = 6, secondArray[3] = 7

firstArray[4] = 8, secondArray[4] = 9

After Swap

firstArray[0] = 1, secondArray[0] = 0

firstArray[1] = 3, secondArray[1] = 2

firstArray[2] = 5, secondArray[2] = 4

firstArray[3] = 7, secondArray[3] = 6

firstArray[4] = 9, secondArray[4] = 8

Answer 1

If you have any doubts, please give me comment...

#include<stdio.h>

int main(){

    const int n = 5;

    int firstArray[n], secondArray[n];

    int i, k=0, temp;

    for(i=0, k=0; k<n; i+=2, k++){

        firstArray[k] = i;

        secondArray[k] = i+1;

    }

    printf("Before Swap\n");

    for(i=0; i<n; i++){

        printf("firstArray[%d] = %d, secondArray[%d] = %d\n", i, firstArray[i], i, secondArray[i]);

    }

    //swapping

    for(i=0; i<n; i++){

        temp = firstArray[i];

        firstArray[i] = secondArray[i];

        secondArray[i] = temp;

    }

    printf("After Swap\n");

    for(i=0; i<n; i++){

        printf("firstArray[%d] = %d, secondArray[%d] = %d\n", i, firstArray[i], i, secondArray[i]);

    }

    return 0;

}